8n^2+32n-30=0

Solution for 8n^2+32n-30=0 equation:

8n^2+32n-30=0

a = 8; b = 32; c = -30;
Δ = b2-4ac
Δ = 322-4·8·(-30)
Δ = 1984
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1984}=\sqrt{64*31}=\sqrt{64}*\sqrt{31}=8\sqrt{31}$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-8\sqrt{31}}{2*8}=\frac{-32-8\sqrt{31}}{16}
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+8\sqrt{31}}{2*8}=\frac{-32+8\sqrt{31}}{16}
$